Motivation. Extend class, that implement interface I
, with interface derived from I
, without virtual inheritance. C++ does not allow to do static_cast
downcast for class with virtual inheritance.
Have this:
// PURE interfaces per se. No data. All public.
struct IView{
virtual void setOnClick() = 0;
};
struct ITextView : virtual IView {
virtual void setText() = 0;
};
// implementation
struct View : virtual IView {
virtual void setOnClick() override {
std::cout << "setting OnClick!" << std::endl;
}
};
struct TextView : virtual ITextView, virtual View {
virtual void setText() override {
std::cout << "setting text!" << std::endl;
}
};
Without performance overhead of this:
// can do upcast with static_cast
TextView text;
ITextView* i_text = static_cast<ITextView*>(&text);
IView* i_view = static_cast<IView*>(i_text);
// (!) but must use dynamic_cast for downcast
ITextView* text_view = dynamic_cast<ITextView*>(i_view);
Solving the problem
Forwarding
First what come to mind is just forward all IView
functions implemented by View
to TxtView
, like this:
struct TextView : ITextView, View {
virtual void setText() override {
std::cout << "setting text!" << std::endl;
};
virtual void setOnClick() override {
View::setOnClick();
}
};
And that’s ok. If we forget something to forward / implement, compiler will remind it. But if we have, like +8 functions in each level, most part of our classes will consists from forward functions. The higher inheritance level, the more functions we should forward.
Forwarding with macro
We need some machinery to forward base interface-implementing functions. Meta-programming with reflections would do a great help here, but… we don’t have them… yet… So, for now, we can do forward macro for each interface, like:
struct IView{
virtual void setOnClick() = 0;
};
#define forward_IView(To_class)\
virtual void setOnClick() override {\
To_class::setOnClick();\
}
And then :
struct TextView : ITextView, View {
forward_IView(View)
virtual void setText() override {
std::cout << "setting text!" << std::endl;
};
};
Let alone bogus process of writing macro like this, we have another problem. If we, by any reason, would want to override forwarded function, we obviously couldn’t:
struct TextView : ITextView, View {
forward_IView(View)
virtual void setText() override {
std::cout << "setting text!" << std::endl;
};
// compiler error, redifinition
virtual void setOnClick() override {
std::cout << "clicking" << std::endl;
}
};
Solution
Have Forward
helper per each interface:
struct IView : IBase {
virtual void setOnClick() = 0;
template<class T, class ...Interfaces>
struct Forward : T, Interfaces... {
virtual void setOnClick() override {
T::setOnClick();
}
};
};
struct ITextView : IView {
virtual void setText() = 0;
template<class T, class ...Interfaces>
struct Forward : IView::Forward<T, Interfaces...> {
virtual void setText() override {
T::setText();
}
};
};
Use as:
struct TextView : IView::Forward<View, ITextView> {
virtual void setText() override {
std::cout << "setting text! i: " << std::endl;
};
};
You still need to write simple forward code, for each function in your interface. But now only once per interface. [This can be completly automated, if you work with clang compiler fork with experimental reflection/meta-programming support]
Size-wise, solution equivalent to class with virtual-inheritance. Your interface classes MUST be zero-size.
Update
As NotAYakk pointed out, there is more efficient solution:
struct IView{
virtual void setOnClick() = 0;
};
struct ITextView : IView {
virtual void setText() = 0;
};
// implementation
template<class Interface = IView>
struct View : Interface {
virtual void setOnClick() override {
std::cout << "setting OnClick!" << std::endl;
}
};
template<class Interface = ITextView>
struct TextView : View<Interface> {
virtual void setText() override {
std::cout << "setting text!" << std::endl;
}
};
With c++17 class template argument deduction use as:
TextView text;
IView* i = &text;
ITextView* i_tv = static_cast<ITextView*>(i);
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